Tuesday 14 December 2021

Basic Proportionality Theorem for a Triangle

Basic Proportionality Theorem for a Triangle

Objective
To verify the basic proportionality theorem by using parallel lines board, triangle cut outs.

Basic Proportionality Theorem
If a line is drawn parallel to one side of a triangle, to intersect the other two sides at distinct points, the other two sides are divided in the same ratio.

Prerequisite Knowledge

  1. Statement of Basic Proportionality theorem.
  2. Drawing a line parallel to a given line which passes through a given point.

Materials Required
White chart paper, coloured papers, geometry box, sketch pens, fevicol, a pair of scissors, ruled paper sheet (or Parallel line board).

Procedure

  1. Cut an acute-angled triangle say ABC from a coloured paper.
  2. Paste the ΔABC on ruled sheet such that the base of the triangle coincides with ruled line.
    NCERT Class 10 Maths Lab Manual - Basic Proportionality Theorem for a Triangle 1
  3. Mark two points P and Q on AB and AC such that PQ || BC.
    NCERT Class 10 Maths Lab Manual - Basic Proportionality Theorem for a Triangle 2
  4. Using a ruler measure the length of AP, PB, AQ and QC.
  5. Repeat the same for right-angled triangle and obtuse-angled triangle.
  6. Now complete the following observation table.

Observation
NCERT Class 10 Maths Lab Manual - Basic Proportionality Theorem for a Triangle 3
Result
In each set of triangles, we verified that \frac { AP }{ PB } =\frac { AQ }{ QC }

Learning Outcome
In all the three triangles the Basic Proportionality theorem is verified.

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